KeonteA31732 KeonteA31732
  • 03-11-2022
  • Mathematics
contestada

The length of a rectangle is 4 in longer than its width. If the perimeter of the rectangle is 362 in, find it's area.

Respuesta :

KaleahO211785 KaleahO211785
  • 03-11-2022

The length of a rectangle is 4 in longer than its width, which means

Length = 4 in + width

P = 362 in = 2L + 2W

362in = 2(4 in + W) + 2W = 8in+2W+2W = 8in + 4W

362in = 8in + 4W

Solve for W

362 in - 8in = 4W

354 = 4W

354/4 = W

88.5 = W

Replace W in the Length

Length = 4 in + W

Length = 4 in + 88.5in

Length = 92.5in

The formula for the area is A = Length * Width = L * W

Replace the values and find the area

A = L* W

A = 92.5in * 88.5in

A = 8186.25 in²

Answer Link

Otras preguntas

Pls help me with this
In the modern time school is declared as a peace zone area . But school are freguently closed due to the different issue and stracts . In your view what should
u( w f +u ) = m + j solve for u : u= solve for f :F=
Can ya'll help me? I have tried to do it but I keep getting it wrong :(
How can report writers decide what type of graphic to use in a report?
pls answer this for me :)
this one aswell haha i dont know any of these
a) Briefly explain ONE argument that supports the view that the Spanish-American War was caused by humanitarian concerns. b) Briefly explain ONE argument that s
20. Free-Body Diagram You are sitting in the back seat of a car going around a curve to the right. Sketch motion and free-body diagrams to answer these questio
a The diameter of a semicircle is 6 yards. What is the semicircle's perimeter? d=6 yd Use 3.14 for a.