FutureU788263 FutureU788263
  • 03-11-2022
  • Mathematics
contestada

14. Solve for x and y. b x+13 5Y Linesa.b, and care perpendicular bisectors

Respuesta :

MilianC579022 MilianC579022
  • 03-11-2022

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data

3x - 9 ===> A

x + 13 ===> C

5y ====> B

Step 02:

We must apply the properties of triangles.

x + 13 = 5y eq.1

3x - 9 = x + 13 eq.2

eq .2

3x - 9 = x + 13

3x + x = 13 + 9

4x = 22

x = 22/4 = 11 / 2

eq. 1

x + 13 = 5 y

[tex]\begin{gathered} \frac{11}{2}+13=5y \\ \frac{11+26}{2}=5y \end{gathered}[/tex][tex]\begin{gathered} \frac{37}{2\cdot5}=y \\ \frac{37}{10}=y \end{gathered}[/tex]

The answer is:

x = 11 / 2

y = 37 / 10

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