titubrahnu
titubrahnu titubrahnu
  • 01-04-2021
  • Mathematics
contestada


[tex] \sqrt{ {4 a}^{2} + {12a}^{2} } [/tex]
​

Respuesta :

LittleAngel36
LittleAngel36 LittleAngel36
  • 02-04-2021

Answer:

The answer is 4a

Step-by-step explanation:

1) Simplify 4a² + 12a² to 16a².

[tex] \sqrt{ {16a}^{2} } [/tex]

2) Use this rule:

[tex] \sqrt{ab} = \sqrt{a} \sqrt{b} [/tex]

[tex] \sqrt{16} \sqrt{ {a}^{2} } [/tex]

3) Since 4 × 4 is 16, the square root of 16 is 4.

[tex]4 \sqrt{ {a}^{2} } [/tex]

4) Simplify.

[tex]4a[/tex]

Therefor, the answer is 4a.

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