myannanation
myannanation myannanation
  • 03-12-2020
  • Mathematics
contestada

Pleaseee Helppppp
Find the minimum value of the function f(x) = x2 + 12x + 31.5 to the
nearest hundredth.

Respuesta :

autumn0503 autumn0503
  • 03-12-2020

Answer:

The answer is pie

Step-by-step explanation:

I know best

Answer Link
SageRage
SageRage SageRage
  • 03-12-2020

Answer:

x = -6.00 (rounded to nearest hundredth)

Step-by-step explanation:

  • for a quadratic equation, [tex]h(x)=ax^2+bx+c[/tex]  
  • we have [tex]f(x)=x^2+12x+31.5[/tex]
  • a = 1
  • b = 12
  • to find minimum use equation [tex]x=\frac{-b}{2a}[/tex]
  • [tex]x=\frac{-b}{2a}\\x=\frac{-(12)}{2(1)}\\x=\frac{-12}{2}=-6[/tex]
Answer Link

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