Answer:
Explanation:
mass of copper = 200 g at temperature 100°C
mass of water = 1000 g at 20⁰C
Let the final temperature be T .
specific heat of copper = .385 J per gram
specific heat of water = 4.182 J per gram
heat lost = mass x specific heat x fall of temperature
heat lost by copper
= 200 x .385 x ( 100 - T )
heat gained by water
= 1000 x 4.182 x ( T - 20 )
heat lost by copper = heat gained by water
200 x .385 x ( 100 - T ) = 1000 x 4.182 x ( T - 20 )
7700 - 77 T = 4182 T - 83640
4259 T = 91340
T = 21.44⁰C .
