Why does the equation 8(5c-2)=10(32+4c) have no solution

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11-09-2016
Mathematics

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Why does the equation 8(5c-2)=10(32+4c) have no solution

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Prove that (x^5)-(x^2)+2x +3=0 has at least one real root. Prove that x=cosx has at least one solution.

Nick777 Nick777 · Answer 1 · 2016-09-11T23:18:12+02:00

Nick777 Nick777

11-09-2016

40c-16=320+40c
40c=336=40c
Here is where you answer is when you combine like term you get 40c-40c which means the variable cancels out meaning you have no variable to solver for, so in the end you get no solution.
Hope This Helps :D

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