purpleraygun82
purpleraygun82 purpleraygun82
  • 13-05-2020
  • Chemistry
contestada

How many moles of O₂ are needed to react completely with 35.0 mol of FeCl₃? *

Respuesta :

valeherrera333 valeherrera333
  • 13-05-2020

Answer:

52.5 mol O2

Explanation:

4 FeCl3 + 6 O2 -> 2 Fe2O3 +6 Cl2

4 mol FeCl3      -> 6 mol O2

35.0 mol FeCl3 -> x

x= (35.0 mol FeCl3 * 6 mol O2)/4 mol FeCl3

x=52.5 mol O2

Answer Link
xinyihuang2004 xinyihuang2004
  • 13-05-2020

Answer is A, 26.3 mol.

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