The power dissipated is 300 W
Explanation:
The electric power dissipated in an electric circuit is given by the equation:
[tex]P=I^2R[/tex]
where
P is the power dissipated
I is the current
R is the resistance
For the circuit in this problem, we have:
I = 5 A is the current
[tex]R=12\Omega[/tex] is the resistance
Substituting, we find the power dissipated:
[tex]P=(5)^2(12)=300 W[/tex]
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