Answer:
Time of race = 10.18 s
Explanation:
She keeps this acceleration for 17 m and then maintains the velocity for the remainder of the 100-m dash
Time to travel 17 m can be calculated
s = ut + 0.5at²
17 = 0 x t + 0.5 x 3.89 x t²
t = 2.96 s
Velocity after 2.96 seconds
v = 3.89 x 2.96 = 11.50 m/s
Remaining distance = 100 - 17 = 83 m
Time required to cover 83 m with a speed of 11.50 m/s
[tex]t=\frac{83}{11.50}=7.22s[/tex]
Time of race = 2.96 + 7.22 = 10.18 s
